document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088909>Question 1088909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 267 with 166 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.\r<BR>\n" );
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document.write( "98% C.I. =\r<BR>\n" );
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document.write( "Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703219 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CI0.98)=phat +/- 2.326 *sqrt (p(1-p))/n<BR>\n" );
document.write( "=0.622+/- 2.326 * sqrt (0.622*0.378)/267; sqrt term is 0.0297; product is 0.069<BR>\n" );
document.write( "interval is (0.553, 0.691) </SPAN>\n" );
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