document.write( "Question 1088851: log1/64 base 0.25
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Algebra.Com's Answer #703176 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Write this as the inverse function which is:
\n" ); document.write( "\"+.25%5Ex+=+1%2F64+\"
\n" ); document.write( "\"+%281%2F4%29%5Ex+=+%28+1%2F4+%29%5E3+\"
\n" ); document.write( "\"+x+=+3+\"
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