document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088767>Question 1088767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=x+7 and f(g(2))=3, which if the following functions could be g(x)?<BR>\n" );
document.write( "A. X-6<BR>\n" );
document.write( "B. X+6<BR>\n" );
document.write( "C. 3x-1<BR>\n" );
document.write( "D. 2x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703098 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the first is substituted, the function is x-6+7=x+1, and f(2)=3.<BR>\n" );
document.write( "If the second is substituted, the function is x+13, doesn't work<BR>\n" );
document.write( "the third becomes 3x+6, which doesn't work<BR>\n" );
document.write( "The fourth becomes 2x+6 which also doesn't work.<BR>\n" );
document.write( "A. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );