document.write( "Question 1088769: Solve the system: x + y + z = 3, 2x – y + 3z = 3, x - 2y + 3z = 0 \n" ); document.write( "
Algebra.Com's Answer #703094 by Boreal(15235)\"\" \"About 
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x + y + z = 3, 2x – y + 3z = 3, x - 2y + 3z = 0
\n" ); document.write( "x+y+z=3
\n" ); document.write( "2x-y+3z=3
\n" ); document.write( "add
\n" ); document.write( "3x+4z=6
\n" ); document.write( "-------------
\n" ); document.write( "2x+2y+2z=6, double first
\n" ); document.write( "x-2y+3z=0
\n" ); document.write( "3x+5z=6
\n" ); document.write( "subtract
\n" ); document.write( "-z=0
\n" ); document.write( "z=0
\n" ); document.write( "x=2
\n" ); document.write( "y must be 1
\n" ); document.write( "(2, 1, 0)
\n" ); document.write( "Can be done with matrices, but eliminating one variable twice makes it two simultaneous equations and can be done that way, too.
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