document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088757>Question 1088757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After 1885 in a hospital, the number of births increase is shown with this equation- N=150(2^t/15) where n represents the number of births and t is the number of years since 1885. In what year would the annual birth tae in the hospital reach 3840? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703080 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3840=150(2^(t/15)<BR>\n" );
document.write( "divide both sides by 150<BR>\n" );
document.write( "25.6=2^(t/15)<BR>\n" );
document.write( "take log2 of both sides<BR>\n" );
document.write( "log2 25.6=t/15<BR>\n" );
document.write( "find log 2 (25.6) using change of base<BR>\n" );
document.write( "log 10(25.6)/log 10(2)=4.678<BR>\n" );
document.write( "That equals t/15<BR>\n" );
document.write( "t=70.17 years or 1955 and it will exceed it in early 1956.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );