document.write( "Question 1088726: The​ half-life of​ carbon-14 is 5600 years. If a piece of charcoal made from the wood of a tree shows only 73​% of the​ carbon-14 expected in living​ matter, when did the tree​ die? \r
\n" ); document.write( "\n" ); document.write( "The tree died about ______ years ago?
\n" ); document.write( "​(Do not round until the final answer. Then round to the nearest whole​ number.)
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Algebra.Com's Answer #703074 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
formula is:\r
\n" ); document.write( "\n" ); document.write( "\"F+=+P%2Ae%5E%28kt%29\" where:\r
\n" ); document.write( "\n" ); document.write( "\"F\" = future amount
\n" ); document.write( "\"P\" = present amount
\n" ); document.write( "\"k+\"= constant of proportion.
\n" ); document.write( "\"t\" = time\r
\n" ); document.write( "\n" ); document.write( "half life of carbon is given by the equation:\r
\n" ); document.write( "\n" ); document.write( "\".5+=+e%5E%285600k%29\" because:\r
\n" ); document.write( "\n" ); document.write( "half life of carbon is \"5600\" years.\r
\n" ); document.write( "\n" ); document.write( "solve for \"k\" and then you can solve the problem.\r
\n" ); document.write( "\n" ); document.write( "take log of both sides of equation of \".5+=+e%5E%285600k%29\" to get:\r
\n" ); document.write( "\n" ); document.write( "\"log%28.5%29+=+log%28e%5E%285600k%29%29\"\r
\n" ); document.write( "\n" ); document.write( "this becomes:\r
\n" ); document.write( "\n" ); document.write( "\"log%28.5%29+=+5600k+%2A+log%28e%29\"\r
\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by \"5600%2Alog%28e%29\" to get:\r
\n" ); document.write( "\n" ); document.write( "\"k+=+log%28.5%29%2F%285600%2Alog%28e%29%29\"\r
\n" ); document.write( "\n" ); document.write( "solve for \"k+\"to get:\r
\n" ); document.write( "\n" ); document.write( "\"k+=+-.301029996+%2F+%285600%2A.434294482%29\" which becomes:\r
\n" ); document.write( "\n" ); document.write( "\"k+=+-.000123776+\"\r
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\n" ); document.write( "\n" ); document.write( "if the tree has only \"73\"%=\"0.73\" of the carbon left, then your equation of: \r
\n" ); document.write( "\n" ); document.write( "\"F+=+P+%2A+e%5E%28kt%29\" becomes:\r
\n" ); document.write( "\n" ); document.write( "\".73+=+1%2Ae%5E%28k%2At%29\" which becomes:\r
\n" ); document.write( "\n" ); document.write( "\".73+=+e%5E%28-.000123776%2At%29\"\r
\n" ); document.write( "\n" ); document.write( "take the log of both sides of this equation to get:\r
\n" ); document.write( "\n" ); document.write( "\"log%28.73%29+=+log%28e%5E%28-.000123776%2At%29%29\" which becomes:\r
\n" ); document.write( "\n" ); document.write( "\"log%28.73%29+=+-.000123776%2At%2Alog%28e%29\"\r
\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by \"-.000123776%2Alog%28e%29\" to get:\r
\n" ); document.write( "\n" ); document.write( "\"t+=+log%28.73%29+%2F+%28-.000123776%2Alog%28e%29%29\"\r
\n" ); document.write( "\n" ); document.write( "solve for \"t\" to get:\r
\n" ); document.write( "\n" ); document.write( "\"t+=+2542.58\" years\r
\n" ); document.write( "\n" ); document.write( "Then round to the nearest whole number:\"t+=+2543\" years\r
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