document.write( "Question 1088728: Find the principal needed now to get the given amount; that is, find the present value.
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document.write( "To get $3000 after 33/4 years at 5% compounded daily.\r
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document.write( "The present value of $ 3000 is?$______
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document.write( "(Round to the nearest cent as needed.) \n" );
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Algebra.Com's Answer #703025 by Theo(13342)![]() ![]() You can put this solution on YOUR website! f = p * (1+r) ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 3000 \n" ); document.write( "p = what you want to find. \n" ); document.write( "r = 5% / 365 / 100 = .0001369863014 \n" ); document.write( "n = 33 * 365 = 12045\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number of days in a year can be 360, 365, 365.4, or some other value depending on how you look at the number of days in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i chose 365.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the number of days in a year is different than that, you can redo the calculations using the other value for number of days in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "interest rate = interest rate % divided by 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3000 = p * (1 + .0001369863014) ^ 12045\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3000 = p * 5.206391456\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for p to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 3000 / 5.206391456 = 576.2148362\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an investment of 576.2148362 will becomes 3000 in 33 years at 5% compounded daily.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "576.2148362 * (1 + 1.369863014 * 10 ^ -4) ^ (33 * 365) = 3000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note that 1.369863014 * 10 ^ -4 is equal to .0001369863014\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note that 33 * 365 = 12045\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it all checks out, assuming 365 days in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i assumed 33 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'm not sure what you means by 33/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could have meant 33 or 34 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could have meant 33/4 = 8.25 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use the same formula and make any assumption you want and you'll get the answer you're looking for.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "just keep in mind.....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = annual interest rate % divided by number of compounding periods per year divided by 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = number of years times number of compounding periods per year.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |