document.write( "Question 1088662: An excursion boat travels up river to a landing than returns to its starting point. The trip upriver takes 2.3 hours, and the trip back takes 1.8 hours. If the average speed on the return trip is 5 mph faster than the trip up river, what is the boat’s speed up river? Hint: Distance = rate * time. Draw a table.ate * time. Draw a table. \n" ); document.write( "
Algebra.Com's Answer #703008 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( "------------------ \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "-------------------------- \n" ); document.write( "(2) \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "------------------ \n" ); document.write( "The speed upriver is 18 mi/hr \n" ); document.write( "----------------- \n" ); document.write( "To make a table, you have: \n" ); document.write( "[ upriver speed, s ], [ downriver speed, s+5 ], \n" ); document.write( "[ upriver time ], [ downriver time ] \n" ); document.write( "[ upriver distance, d ] = [ downriver distance, d ]\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |