document.write( "Question 1088656: A ship leaves port at 6am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15mph. How far apart, to the nearest tenth of a mile, are the two ships at 11pm? \n" ); document.write( "

Algebra.Com's Answer #702967 by natolino_2017(77) $\"\"$ $\"About$

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First, let's see the distance travelled for the first ship\r
\n" ); document.write( "\n" ); document.write( "Distance1 = 12 Mile/hr*17 hours = 204 Miles.\r
\n" ); document.write( "\n" ); document.write( "Second distance is the one travelled of the second ship\r
\n" ); document.write( "\n" ); document.write( "Distance2 = 15 Mile/hr*12 hours =180 Miles.\r
\n" ); document.write( "\n" ); document.write( "as the first ship travelled to the east and the second ship travels to the north, the 204 miles and 180 miles are the legs of a rectangle triangle.\r
\n" ); document.write( "\n" ); document.write( "The distance is the hypotenuse of the triangle:\r
\n" ); document.write( "\n" ); document.write( " $\"distance+=+%28+sqrt%28+204%5E2+%2B280%5E2+%29%29+\"$ = 272.1 Miles\r
\n" ); document.write( "\n" ); document.write( "@natolino_
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