document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088646>Question 1088646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ml of 4% and 1% solution are needed to make 1800 ml of 2% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702945 by </B><A HREF=/tutors/aboutme.mpl?userid=natolino_2017><B>natolino_2017(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=natolino_2017><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x: ml. of the 4% solution<BR>\n" );
document.write( "    y: ml. of the 1% solution\r<BR>\n" );
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document.write( "x+y = 1,800 (total solution)<BR>\n" );
document.write( "0.04x +0.01y = 0,02(1,800) = 36 (total component)\r<BR>\n" );
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document.write( "Solving x=600 ml. and y= 1,200 ml.\r<BR>\n" );
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document.write( "So answer is we need 600 ml of the 4% and 1,200 ml of the 1% solution.\r<BR>\n" );
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document.write( "In a more general case, we need 1/3 of the 4% solution and 2/3 of the 1% solution to make a solution of 2%.\r<BR>\n" );
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document.write( "4%x/3+ 1%*2x/3 = 2%*x when x is the total  ml. of the solution.\r<BR>\n" );
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document.write( "@natolino_\r<BR>\n" );
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document.write( " </SPAN>\n" );
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