document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088599>Question 1088599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3^-3x = 81\r<BR>\n" );
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document.write( "I started here by taking the log of both sides to solve for x.  My final answer ended up 4/-3, or -1.333.  This was marked wrong.  Any insight? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702877 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^(-3x) = 81<BR>\n" );
document.write( "log(3^(-3x)) = log(81)<BR>\n" );
document.write( "Since the logarithm of a number raised to a power is the power times the logarithm of the number:<BR>\n" );
document.write( "((-3)x)(log(3)) = log(81)<BR>\n" );
document.write( "(-3)x = log(81)/log(3)<BR>\n" );
document.write( "(-3)x = log_3(81) = 4<BR>\n" );
document.write( "x = 4/-3 = -1.3333<BR>\n" );
document.write( "Well, I'm afraid I haven't been of any help since I got the same answer you got and obviously your teacher is looking for a different answer. But I have solved the problem correctly, so whoever is telling you that this is the wrong answer is, in my view, making a mistake. S/he needs to work the problem so s/he can see that the answer book they have is incorrect. Good luck.\r<BR>\n" );
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