document.write( "Question 1088595: John invested 3 times as much money at 12% interest as he did at 8%. If he earned a total of $264 in interest for the year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #702875 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Invested at 8%: x \n" ); document.write( "Invested at 12%: 3x \n" ); document.write( "0.08x+0.12(3x) = 264 \n" ); document.write( "0.08x+0.36x = 264 \n" ); document.write( "0.44x = 264 \n" ); document.write( "x = 600 \n" ); document.write( "3x = 1800 \n" ); document.write( "He invested 600 at 8% and 600*3 = 1800 at 12% \n" ); document.write( "-------------------------------- \n" ); document.write( "Check: \n" ); document.write( "600*.08 = 48 \n" ); document.write( "1800*0.12 = 216 \n" ); document.write( "48+216= 264 correct \n" ); document.write( " \n" ); document.write( " |