document.write( "Question 1088222: Dominique flew her light plane from Buffalo to Cleveland at an land one half the Dominique average speed of 150 km/h. She waited at Cleveland one half the time that she had been in the air on her trip to Cleveland. Returning home, she took a route that was 60 km longer and flew at an average speed of 180 km/h. If the total trip took five hours, how long did she stay in Cleveland? \n" ); document.write( "
Algebra.Com's Answer #702855 by KMST(5328)\"\" \"About 
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\"t\"= time Dominique waited at Cleveland (in hours)
\n" ); document.write( "\"2t\"= time in the air on her trip to Cleveland (in hours)
\n" ); document.write( "\"150%2A%282t%29=300t\"= distance flown on her trip to Cleveland (in km)
\n" ); document.write( "\"300t%2B60\"= distance flown on the return trip (in km)
\n" ); document.write( "\"%28300t%2B60%29%2F180=%285%2F3%29t%2B1%2F3\"= time in the air on the return trip (in hours)
\n" ); document.write( "Adding times,
\n" ); document.write( "\"2t%2Bt%2B%285%2F3%29t%2B1%2F3=5\"
\n" ); document.write( "Multiplying both sides of the equation times 3 to eliminate denominators,
\n" ); document.write( "\"6t%2B3t%2B5t%2B1=15\"
\n" ); document.write( "\"14t%2B1=15\"
\n" ); document.write( "\"14t=15-1\"
\n" ); document.write( "\"14t=14\"
\n" ); document.write( "\"t=1\"
\n" ); document.write( "Dominique waited at Cleveland for \"highlight%281+hour%29\" .
\n" ); document.write( "
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