document.write( "Question 1088545: The length of a rectangle exceeds its width by 6 units. If each dimension were increased by 3 units ,the area would be increased by 57 square miles. Find the dimensions of the original rectangle ive been trying and i cant solve this \n" ); document.write( "
Algebra.Com's Answer #702825 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle exceeds its width by 6 units.
\n" ); document.write( " If each dimension were increased by 3 units ,the area would be increased by 57 square miles.
\n" ); document.write( "Find the dimensions of the original rectangle
\n" ); document.write( ":
\n" ); document.write( "L = (w+6)
\n" ); document.write( "L*W = the area of the original rectangle
\n" ); document.write( "and
\n" ); document.write( "(L+3)*(w+3) = the increased area
\n" ); document.write( "Foil
\n" ); document.write( "Lw + 3L + 3w + 9 = new area
\n" ); document.write( ":
\n" ); document.write( "New area - original area = 57 sq/units
\n" ); document.write( "Lw + 3L + 3w + 9 - Lw = 57
\n" ); document.write( "lw - Lw + 3L + 3w + 9 = 57
\n" ); document.write( "3L + 3w = 57 - 8
\n" ); document.write( "3L + 3w = 48
\n" ); document.write( "simplify, divide by 3
\n" ); document.write( "L + w = 16
\n" ); document.write( "replace L with (w+6)
\n" ); document.write( "w + 6 + w = 16
\n" ); document.write( "2w = 16 - 6
\n" ); document.write( "2w = 10
\n" ); document.write( " w = 5 units is the width of the original rectangle
\n" ); document.write( "then
\n" ); document.write( " 5 + 6 = 11 units is the length
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this, new rectangle is 14 by 8
\n" ); document.write( "14*8 - 11*5 =
\n" ); document.write( "112 - 55 = 57
\n" ); document.write( " \n" ); document.write( "
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