document.write( "Question 13985: The distance of the point (3,0) from the line \"y=%281%2F2%29x%2B1\" \n" ); document.write( "
Algebra.Com's Answer #7028 by longjonsilver(2297)\"\" \"About 
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the quoted line has gradient 1/2.\r
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\n" ); document.write( "\n" ); document.write( "the line through (3,0) to this first line will have a gradient of -2 (look at my Lesson on straight lines, for the reason).\r
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\n" ); document.write( "\n" ); document.write( "So, the second line equation is y=-2x+c... need to find c:\r
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\n" ); document.write( "\n" ); document.write( "0 = -2(3) + c
\n" ); document.write( "0 = -6 + c
\n" ); document.write( "--> c = 6\r
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\n" ); document.write( "\n" ); document.write( "--> equation is y=-2x+6\r
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\n" ); document.write( "\n" ); document.write( "Right, we need to know the coordinates of th epoint where the 2 points cross...ie where the 2 lines are EQUAL...\r
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\n" ); document.write( "\n" ); document.write( "so, we have y = (1/2)x + 1 = -2x + 6
\n" ); document.write( "(1/2)x = -2x + 5
\n" ); document.write( "x = -4x + 10
\n" ); document.write( "5x = 10
\n" ); document.write( "--> x = 2.\r
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\n" ); document.write( "\n" ); document.write( "so from y = -2x + 6, we get
\n" ); document.write( "y = -2(2) + 6
\n" ); document.write( "y = -4 + 6
\n" ); document.write( "y = +2\r
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\n" ); document.write( "\n" ); document.write( "so, point of intersection is (2,2).\r
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\n" ); document.write( "\n" ); document.write( "So now you have 2 points (3,0) and (2,2)...find the length of that line...you do that :-)\r
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\n" ); document.write( "\n" ); document.write( "jon.\r
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