document.write( "Question 1088504: River's chemistry class is doing an experiment in which the students create a 30% hydrochloric acid mixture by mixing a certain amount of 25% solution with a different amount of 50% solution. The amount of 25% solution used is 20 liters less than 5 times the amount of 50% solution used. How much of the 25% solution and the 50% solution are needed in all?
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Algebra.Com's Answer #702790 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the amount of 50% solution to be used. Then the 25% solution would be 5n-20. So:
\n" ); document.write( ".50n+.25(5n-20)=.30(n+5n-20)
\n" ); document.write( ".50n+1.25n-5=.30n+1.5n-6
\n" ); document.write( ".05n=1
\n" ); document.write( "n=20
\n" ); document.write( "They need 20 liters of 50% solution and 80 liters of 25% solution
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