document.write( "Question 1088508: Three consecutive integers have a sum of
\n" ); document.write( "81
\n" ); document.write( ". Find the integers. \n" ); document.write( "
Algebra.Com's Answer #702774 by math_helper(2461)\"\" \"About 
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Let a=smallest of the 3 integers
\n" ); document.write( "a + (a+1) + (a+2) = 81
\n" ); document.write( "3a + 3 = 81
\n" ); document.write( "3a = 78 —> a = 26
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\n" ); document.write( "Ans: The three numbers are 26, 27, and 28
\n" ); document.write( "Check: 26+27+28 = 81 (ok)
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\n" ); document.write( "\n" ); document.write( "Another method. Since the integers are consecutive, 3 times the average (which will be a+1) of the three numbers will be 81:
\n" ); document.write( " 3(a+1) = 81
\n" ); document.write( " a+ 1 = 27
\n" ); document.write( " a = 26 —> the same answer 26, 27, 28 is obtained.\r
\n" ); document.write( "\n" ); document.write( "[ This method works for other evenly spaced integer problems, this particular problem has them spaced one apart. Just be sure to check your work by checking your answer. ]
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