document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088475>Question 1088475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the measure of a complement of a certain angle is equal to 30 more than the measure of a supplement of that angle. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702746 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=angle<BR>\n" );
document.write( "90-x=complement<BR>\n" );
document.write( "3(90-x)=30+(180-x), where 180-x is the supplement of the angle<BR>\n" );
document.write( "270-3x=210-x<BR>\n" );
document.write( "60=2x<BR>\n" );
document.write( "x=30 deg, the angle<BR>\n" );
document.write( "complement is 60 deg<BR>\n" );
document.write( "3*60-30=supplement=150<BR>\n" );
document.write( "supplement is 150 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );