document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96497>Question 96497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe traveled against the wind in a small plane for 3 hours. The return trip with the wind took 2.8 hours. Find the speed of the wind if the speed of the plane in still air is 180mph.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70270 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=distance t=time s=speed w=wind speed<BR>\n" );
document.write( "d=ts<BR>\n" );
document.write( "going: d=3(180-w)=540-3w<BR>\n" );
document.write( "returning: d=2.8(180+w)=504+2.8w<BR>\n" );
document.write( "since the distances are equal: 540-3w=504+2.8w<BR>\n" );
document.write( "add 3w and subtract 504 from each side. 5.8w=36<BR>\n" );
document.write( "w=6.2 mph approx.<BR>\n" );
document.write( "Ed<BR>\n" );
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