document.write( "Question 1088423: Find the domain of the function.
\n" ); document.write( "Domain in the link: http://prntscr.com/fyqy26
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Algebra.Com's Answer #702692 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Given Function:
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\n" ); document.write( "Note: If the image doesn't show up, then it's the function g(x) = 1/(x(x+2))\r
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\n" ); document.write( "\n" ); document.write( "The domain is the set of numbers x where x can be any real number but it cannot be equal to zero, and it also can't be equal to -2
\n" ); document.write( "Why can't x equal these values? Because either value makes the denominator x(x+2) equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "We can see this by solving x(x+2) = 0 for x
\n" ); document.write( "x(x+2) = 0
\n" ); document.write( "x(x+2) = 0
\n" ); document.write( "x=0 or x+2 = 0
\n" ); document.write( "x = 0 or x = -2\r
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\n" ); document.write( "\n" ); document.write( "And we can check each value
\n" ); document.write( "Plug in x = 0
\n" ); document.write( "x(x+2) = 0
\n" ); document.write( "0(0+2) = 0
\n" ); document.write( "0(2) = 0
\n" ); document.write( "0 = 0 \r
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\n" ); document.write( "\n" ); document.write( "Plug in x = -2
\n" ); document.write( "x(x+2) = 0
\n" ); document.write( "-2(-2+2) = 0
\n" ); document.write( "-2(0) = 0
\n" ); document.write( "0 = 0\r
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\n" ); document.write( "\n" ); document.write( "So that shows how x = 0 or x = -2 makes the denominator x(x+2) equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "In set builder notation, the domain would be \r
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\n" ); document.write( "\n" ); document.write( "In interval notation, the domain would be \r
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\n" ); document.write( "\n" ); document.write( "Effectively we're \"gluing\" three intervals together. Or put another way, we're poking holes in the number line at -2 and 0 while leaving any other number as part of the domain.
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