document.write( "Question 1088421: Q
\n" ); document.write( "Alan and Bob walk from school to the library. Alan takes 40 minutes while Bob takes 20 minutes. If they start walking from the school at the same time, how long will it take for Bob to be 2/5 as far as Alan from the library?\r
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Algebra.Com's Answer #702681 by ikleyn(52852)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The Alan's rate is \"D%2F40\" of the distance D to the library per minute.\r\n" );
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document.write( "The Bob's rate is \"D%2F20\" of the distance D to the library per minute.\r\n" );
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document.write( "During t minutes Alan will cover the distance  \"t%2A%28D%2F40%29\", and will be at the distance \"D-t%2A%28D%2F40%29\" from the library.\r\n" );
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document.write( "          while  Bob  will cover the distance  \"t%2A%28D%2F20%29\", and will be at the distance \"D-t%2A%28D%2F20%29\" from the library.\r\n" );
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document.write( "They ask you: find t in the way that\r\n" );
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document.write( "\"D-t%2A%28D%2F20%29\" = \"%282%2F5%29%2A%28D-t%2A%28D%2F40%29%29\".\r\n" );
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document.write( "Cancel D in both sides and multiply both sides by 5. You will get\r\n" );
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document.write( "\"5%2A%281-t%2F20%29\" = \"2%2A%281-t%2F40%29\".\r\n" );
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document.write( "Now multiply by 40 both sides. You will get\r\n" );
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document.write( "5*(40-2t) = 2*(40-t)  ====>  200 - 10t = 80 - 2t  ====>  200 - 80 = 10t - 2t  ====>  8t = 120  ====>  t = 15 minutes.\r\n" );
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document.write( "It is your \r\n" );
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document.write( "Answer.  The time under the question is 15 minutes.\r\n" );
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