document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088420>Question 1088420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square piece of land was increased by 10 yards on each side, and contained 1.5 acres more.  Determine dimensions.\r<BR>\n" );
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document.write( "1 acre = 4840 sq. yds.\r<BR>\n" );
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document.write( "Let x = side of square\r<BR>\n" );
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document.write( "x + 10 = side after increase.\r<BR>\n" );
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document.write( "Unsure how to proceed.  Non-homework. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702674 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> increase in area is (x+10)^2-x^2=x^2+20x+100-x^2=20x+100<BR>\n" );
document.write( "That equals 4840*(1.5)=7260 yds^2<BR>\n" );
document.write( "20x+100=7260 yds^2<BR>\n" );
document.write( "x=358 yds^2.<BR>\n" );
document.write( "The land is (358 yds)^2 and increased to (368 yds)^2<BR>\n" );
document.write( "=26.480 acres initially, and 27.980 acres after.<BR>\n" );
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