document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088376>Question 1088376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1-the sum of number and its squre is 240. The number is......<BR>\n" );
document.write( "2-the sum of three consecutive numbers are 81, then the other number is<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702638 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the number<BR>\n" );
document.write( "In equation form, we have n^2 + n = 240 -> n^2 + n - 240 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(n+15)(n-16) = 0<BR>\n" );
document.write( "This gives to possibilities: n=-15 and n=16\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );