document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088385>Question 1088385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each equation by completing the square. If necessary round to the nearest hundredth.<BR>\n" );
document.write( "y^2+ 10y+8=0 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702637 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2 + 10y + 8 = 0<BR>\n" );
document.write( "y^2 + 10y = -8<BR>\n" );
document.write( "To complete the square, we take 1/2 of the middle term (1st order term) and square it.<BR>\n" );
document.write( "10/2 = 5; 5^2 = 25  <BR>\n" );
document.write( "Then we need to add this value to both sides, so as not to alter the original equation.<BR>\n" );
document.write( "y^2 + 10y + 25 = -8 + 25<BR>\n" );
document.write( "(y+5)^2 = 17<BR>\n" );
document.write( "Thus the solutions are:<BR>\n" );
document.write( "y+5 = +-sqrt(17) -> y = +-sqrt(17) - 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );