document.write( "Question 1088332: One side of a larger square is 8 cm longer than a side of a smaller square. Find the dimensions of both squares if the sum of their perimeters is 128 cm \n" ); document.write( "

Algebra.Com's Answer #702592 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let x be the side length of the smaller square, in centimeters.\r\n" );
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document.write( "Then the length of the larger square is (x+8) cm.\r\n" );
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document.write( "The perimeter of the small square is 4x centimeters.\r\n" );
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document.write( "The perimeter of the larger square is 4(x+8) cm.\r\n" );
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document.write( " We are given the sum of the perimeters:\r\n" );
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document.write( "4x + 4(x+8) = 128   cm.\r\n" );
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document.write( "Simplify and solve for x:\r\n" );
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document.write( "4x + 4x + 32 = 128  ====>  8x = 128 - 32  ====>  8x = 96  ====>  x =  = 12.\r\n" );
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document.write( "Answer.  The side length of the smaller square is 12 cm.\r\n" );
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document.write( "         The side length of the larger square is 12+8 = 20 cm.\r\n" );
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