document.write( "Question 1088305: Solve for x: 1/(x-1)(x-2) + 1/(x-2)(x-3) = 2/3, x is not equal to 1,2,3 \n" ); document.write( "
Algebra.Com's Answer #702562 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! if x is not equal to 1,2,3\r \n" ); document.write( "\n" ); document.write( "we can solve this equation:\r \n" ); document.write( "\n" ); document.write( "(x-3) + (x-1) = 2(x-1)(x-2)(x-3)/3\r \n" ); document.write( "\n" ); document.write( "6x - 12 = 2(x^3-6x^2+11x-6)\r \n" ); document.write( "\n" ); document.write( "x^3-6x^2+8x = 0\r \n" ); document.write( "\n" ); document.write( "x(x^2-6x+8) = 0 \n" ); document.write( "x(x-2)(x-4) = 0 using restriction.\r \n" ); document.write( "\n" ); document.write( "answer is {0,4}.\r \n" ); document.write( "\n" ); document.write( "if we put x=0 on the first equation: 1/2 + 1/6 = 2/3 (true) \n" ); document.write( "if we put x=4 on the first equation: 1/6 + 1/2 = 2/3 (true).\r \n" ); document.write( "\n" ); document.write( "@natolino_ \n" ); document.write( " |