document.write( "Question 1088264: Solve the following problem by writing a system of linear equation
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document.write( "A chemist has two alcohol solutions. One is 2% and the other is 6%. She wants to make 60L of a 5% solution. How much of each solutions must she use? \n" );
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Algebra.Com's Answer #702512 by ikleyn(52858) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let x and y be the volumes (in liters, L) to be mixed.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then one equation is \"the volume\" equation \r\n" ); document.write( "\r\n" ); document.write( "x + y = 60 (liters) (1)\r\n" ); document.write( "\r\n" ); document.write( "for the total volume.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The amount of \"x\" liters of the 2% solution contains 0.02x liters of pure alcohol.\r\n" ); document.write( "\r\n" ); document.write( "The amount of \"y\" liters of the 6% solution contains 0.06y liters of pure alcohol.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the mixture contains 0.02x + 0.06y liters of pure alcohol.\r\n" ); document.write( "\r\n" ); document.write( "From the other side, the mixture contains 0.05*60 liters of pure alcohol.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It gives you the second equation, \"pure alcohol contents equation\"\r\n" ); document.write( "\r\n" ); document.write( "0.02x + 0.06y = 0.05*60 (liters of pure alcohol) (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Combining equations (1) and (2), you have this system of two linear equations for two unknowns\r\n" ); document.write( "\r\n" ); document.write( " x + y = 60, (3)\r\n" ); document.write( "0.02x + 0.06y = 3. (4)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Multiply equation (4) by 100 (both sides). You will get an equivalent system in the form\r\n" ); document.write( "\r\n" ); document.write( " x + y = 60, (5)\r\n" ); document.write( "2x + 6y = 300 (6)\r\n" ); document.write( "\r\n" ); document.write( "To solve it, express x = 60 - y from (5) and substitute into (6) replacing x. You will get\r\n" ); document.write( "\r\n" ); document.write( "2(60-y) + 6y = 300,\r\n" ); document.write( "\r\n" ); document.write( "120 - 2y + 6y = 300,\r\n" ); document.write( "\r\n" ); document.write( "4y = 300 - 120 ====> 4y = 180 ====> y =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is entire bunch of lessons covering various types of mixture problems\r \n" ); document.write( "\n" ); document.write( " - Mixture problems\r \n" ); document.write( "\n" ); document.write( " - More Mixture problems\r \n" ); document.write( "\n" ); document.write( " - Solving typical word problems on mixtures for solutions \r \n" ); document.write( "\n" ); document.write( " - Word problems on mixtures for antifreeze solutions \r \n" ); document.write( "\n" ); document.write( " - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts\r \n" ); document.write( "\n" ); document.write( " - Word problems on mixtures for dry substances like candies, dried fruits\r \n" ); document.write( "\n" ); document.write( " - Word problems on mixtures for dry substances like soil and sand\r \n" ); document.write( "\n" ); document.write( " - Word problems on mixtures for alloys \r \n" ); document.write( "\n" ); document.write( " - Typical word problems on mixtures from the archive\r \n" ); document.write( "\n" ); document.write( " - Advanced mixture problem for three alloys \r \n" ); document.write( "\n" ); document.write( " - OVERVIEW of lessons on word problems for mixtures\r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Read them and become an expert in solution the mixture word problems.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r \n" ); document.write( "\n" ); document.write( " - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Mixture problems\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |