document.write( "Question 96487: How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #70251 by stanbon(75887)\"\" \"About 
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How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze?
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\n" ); document.write( "Antifreeze DATA:
\n" ); document.write( "Amount = 1 gallon :Amt of active ingredient = 1 gallon
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\n" ); document.write( "Water DATA:
\n" ); document.write( "Amount = x gallons ; Amt of active ingredient = 0 gallons
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\n" ); document.write( "Mixture DATA:
\n" ); document.write( "Amount = x+1 gallons ; Amt of active ingredient = 0.60(x+1) = 0.6x + 0.6
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "1 + 0 = 0.6x+0.6
\n" ); document.write( "0.4 = 0.6x
\n" ); document.write( "x = (2/3) gallon of water must be added
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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