document.write( "Question 1088255: Let
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Algebra.Com's Answer #702501 by jim_thompson5910(35256)\"\" \"About 
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The function \"f%28x%29+=+%283x-7%29%2F%28x%2B1%29\" has the horizontal asymptote \"%283x%29%2Fx+=+3%2F1+=+3\". \r
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\n" ); document.write( "\n" ); document.write( "You divide the leading terms where \"x+%3C%3E+0\". \r
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\n" ); document.write( "\n" ); document.write( "As x gets larger and larger, f(x) will approach f(x) = 3.\r
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\n" ); document.write( "\n" ); document.write( "What this means is that any value but y = 3 is possible for the range. \r
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\n" ); document.write( "\n" ); document.write( "If we have \"y+=+%283x-7%29%2F%28x%2B1%29\" and we swapped x and y, then we'd have \"x+=+%283y-7%29%2F%28y%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let's solve for y\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283y-7%29%2F%28y%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28y%2B1%29+=+3y-7\"\r
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\n" ); document.write( "\n" ); document.write( "\"xy%2Bx+=+3y-7\"\r
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\n" ); document.write( "\n" ); document.write( "\"xy-3y+=+-7-x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%28x-3%29+=+-7-x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-7-x%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "which is the inverse function. The denominator of this inverse, x-3, indicates that 3 is not in the domain of the inverse. This confirms that 3 is not in the range of the original function.\r
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\n" ); document.write( "\n" ); document.write( "So the range is the set of all y values such that y is a real number but y cannot equal 3. \r
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\n" ); document.write( "\n" ); document.write( "In set builder notation, we'd say \r
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\n" ); document.write( "\n" ); document.write( "In interval notation, we'd write \r
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\n" ); document.write( "\n" ); document.write( "The big U means \"union\" to essentially \"glue\" the two intervals together.\r
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\n" ); document.write( "\n" ); document.write( "Here's what the graph looks like. The blue dashed line is the horizontal asymptote y = 3 (it goes through the two points (0,3) and (1,3))
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\n" ); document.write( "The green curve approaches the dashed line but it will never cross it or touch it. So this shows us that any output but y = 3 is possible. \r
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