document.write( "Question 1088208: The length of a rectangle is 4 square greater than the width. If each dimension is increased by 3 the new area will be 33 square inches larger. Find the dimensions of the original rectangle. \n" ); document.write( "

Algebra.Com's Answer #702465 by Fombitz(32388) $\"\"$ $\"About$

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$\"L=4%2BW\"$
\n" ); document.write( "For a rectangle,
\n" ); document.write( " $\"A=L%2AW\"$
\n" ); document.write( "So,
\n" ); document.write( " $\"LW%2B33=%28L%2B3%29%28W%2B3%29\"$
\n" ); document.write( "Substituting from above,
\n" ); document.write( " $\"%284%2BW%29W%2B33=%284%2BW%2B3%29%28W%2B3%29\"$
\n" ); document.write( " $\"4W%2BW%5E2%2B33=%28W%2B7%29%28W%2B3%29\"$
\n" ); document.write( " $\"W%5E2%2B4W%2B33=W%5E2%2B10W%2B21\"$
\n" ); document.write( " $\"4W%2B33=10W%2B21\"$
\n" ); document.write( " $\"6W=12\"$
\n" ); document.write( " $\"W=2\"$ $\"in\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"L=4%2B2\"$
\n" ); document.write( " $\"L=6\"$ $\"in\"$
\n" ); document.write( " \n" ); document.write( "

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