document.write( "Question 96475This question is from textbook College Algebra
\n" ); document.write( ": The problem is i to the -10th power. I don't even know how to begin to start. The example in the book of i to the -3rd=i to the -4 x i and I don't understand why. Can you give me another example that might work like this one? \n" ); document.write( "
Algebra.Com's Answer #70240 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"i+=+sqrt%28-1%29+\"
\n" ); document.write( "\"i%5E2+=+-1+\"
\n" ); document.write( "\"i%5E3+=+%28i%29%28i%5E2%29+\" giving \"i%5E3+=+-i+\"
\n" ); document.write( "\"i%5E4+=+%28i%5E2%29%5E2+\" giving \"i%5E4+=+%28-1%29%5E2+\" and hence \"i%5E4+=+1+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "After this, the next powers just return through the same 4 values, so \"i%5E5+=+i\" etc.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, \"i%5E10+\" is the same as \"i%5E2\" which is -1.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Anything as a negative power, like \"a%5E%28-n%29\" means \"1%2F%28a%5En%29\", so 1/(-1) is -1. That is your answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "jon
\n" ); document.write( "
\n" ); document.write( "
\n" );