document.write( "Question 1088136: Find an equation of the circle whose center is at the point (-3 , 6) and is tangent to the y axis. \r
\n" ); document.write( "\n" ); document.write( "I figure the answer would be (x+3)^2+(y-6)^2=9 but however at this moment there isn't anyway to prove the answer to whether to be correct or wrong. Thank you very much!
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Algebra.Com's Answer #702393 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use the general equation of a circle of radius R centered at (h,k),
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"
\n" ); document.write( "\"%28x%2B3%29%5E2%2B%28y-6%29%5E2=R%5E2\"
\n" ); document.write( "Since it's tangent to the y-axis, (0,6) is also on the circle,
\n" ); document.write( "\"%280%2B3%29%5E2%2B%286-6%29%5E2=R%5E2\"
\n" ); document.write( "\"R%5E2=9\"
\n" ); document.write( "So,
\n" ); document.write( "\"%28x%2B3%29%5E2%2B%28y-6%29%5E2=9\"
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