document.write( "Question 1088136: Find an equation of the circle whose center is at the point (-3 , 6) and is tangent to the y axis. \r
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document.write( "I figure the answer would be (x+3)^2+(y-6)^2=9 but however at this moment there isn't anyway to prove the answer to whether to be correct or wrong. Thank you very much! \n" );
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Algebra.Com's Answer #702393 by Fombitz(32388) You can put this solution on YOUR website! Use the general equation of a circle of radius R centered at (h,k), \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Since it's tangent to the y-axis, (0,6) is also on the circle, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |