document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96478>Question 96478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be evaporated from 32 ounces of a 4% salt solution to make a 6% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70238 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of water that must evaporate\r<BR>\n" );
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document.write( "Now we know that the amount of pure salt in the original solution (0.04)(32)) has to equal the amount of pure salt in the final solution after evaporation has taken place ((0.06(32-x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.04(32)=0.06(32-x)  get rid of parens\r<BR>\n" );
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document.write( "1.28=1.92-0.06x  subtract 1.92 from both sides\r<BR>\n" );
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document.write( "1.28-1.92=1.92-1.92-0.06x  collect like terms\r<BR>\n" );
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document.write( "-0.64=-0.06x divide both sides by -0.06\r<BR>\n" );
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document.write( "x=10.66667 oz---------------amount of pure water that must evaporate\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.04(32)=0.06(21.33333)\r<BR>\n" );
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document.write( "1.28~1.28\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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