document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088115>Question 1088115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem:A sum of money at compound inerest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702367 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with P<BR>\n" );
document.write( "in 3 years, one has 3P<BR>\n" );
document.write( "in 3 more years, one has 9P<BR>\n" );
document.write( "6 years<BR>\n" );
document.write( "check<BR>\n" );
document.write( "P=Poe^(rt)<BR>\n" );
document.write( "P/Po=9<BR>\n" );
document.write( "9=e^(rt)<BR>\n" );
document.write( "ln 9=rt<BR>\n" );
document.write( "ln9/6=t=0.3662<BR>\n" );
document.write( "---------------See if 36.62% interest triples money in 3 years<BR>\n" );
document.write( "P=Po*e^(.03662*3)<BR>\n" );
document.write( "P/Po=e^(1.0986)=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );