document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1088101>Question 1088101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jean is visiting her grandparents in Houston for 7 days. She wants to arrange a lunch with friends. If she picks a day at random, there is a 30% chance that all of her friends will be available to meet for lunch. What is the probability that all her friends are available to meet for lunch on 4 different days?<BR>\n" );
document.write( "a. 9.7%<BR>\n" );
document.write( "b. 22.7%<BR>\n" );
document.write( "c. 2.3%<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702366 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it is 7C4(0.3)^4*(0.7)^3<BR>\n" );
document.write( "=35*0.0081*0.343<BR>\n" );
document.write( "=0.097<BR>\n" );
document.write( "9.7%<BR>\n" );
document.write( "A </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );