document.write( "Question 1088005: Solve the following equation
\n" ); document.write( "A) 9 log 5 base x = log x base 5\r
\n" ); document.write( "\n" ); document.write( "B) log x/2 base 8 = log x base 2
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Algebra.Com's Answer #702351 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
Solve the following equation
\n" ); document.write( "A) 9 log 5 base x = log x base 5
\n" ); document.write( "B) log x/2 base 8 = log x base 2\r
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\n" ); document.write( "\n" ); document.write( "A) I don't see how to solve this without using an iterative technique
\n" ); document.write( " \"+9log%28x%2C%285%29%29+=+log%285%2C%28x%29%29+\"
\n" ); document.write( " \"+log%28x%2C%285%29%29+=+%281%2F9%29%2Alog%285%2C%28x%29%29+\"
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\n" ); document.write( "\n" ); document.write( "— Maybe another tutor has a better solution. I would be tempted to iterate the last equation until it is (close enough to) zero. \r
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\n" ); document.write( "This one is easily solved\r
\n" ); document.write( "\n" ); document.write( "B) \"+log%288%2C+%28x%2F2%29%29+=+log%282%2C%28x%29%29+\"
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\n" ); document.write( " \"+matrix%281%2C3%2C++x%2F2+%2C+%22=%22%2C+x%5E3+%29+\"
\n" ); document.write( " \"+matrix%281%2C3%2C++1%2F2+%2C+%22=%22%2C+x%5E2+%29+\"
\n" ); document.write( " \"+highlight%28+matrix%281%2C3%2C++x+%2C+%22=%22%2C++sqrt%282%29%2F2%29+%29+\"\r
\n" ); document.write( "\n" ); document.write( "——
\n" ); document.write( "7/18/17 - I can't believe I overlooked that property, \"+log%28a%2Cb%29+=+1%2F%28log%28b%2Ca%29%29+\", which is easy enough to derive from the change-of-base calculation. Thanks tutor Ikleyn!\r
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