document.write( "Question 1087884: For sin a=-3/5 with terminal side in QIII and tan B=-5/12 with terminal side in QIV, find cos(a-B).\r
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Algebra.Com's Answer #702349 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Draw a picture of the two given angles in their \r\n" );
document.write( "respective quadrants.  \r\n" );
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document.write( "Since \"SINE+=OPPOSITE%2FHYPOTENUSE\", make the opposite side\r\n" );
document.write( "of the angle 'a' nearest the x-axis be the numerator of -3/5,\r\n" );
document.write( "which is -3, and the hypotenuse be the denominator of -3/5,\r\n" );
document.write( "which is 5.\r\n" );
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document.write( "Since \"TANGENT+=OPPOSITE%2FADJACENT\", make the opposite side\r\n" );
document.write( "of the angle 'B' nearest the x-axis be the numerator of -5/12,\r\n" );
document.write( "which is -5, and the adjacent be the denominator of -5/12,\r\n" );
document.write( "which is 12.  Use the Pythagorean theorem to calculate the \r\n" );
document.write( "adjacent side of angle 'a' to be -4 (negative because it goes\r\n" );
document.write( "to the left.  Also use the Pythagorean theorem to calculate the \r\n" );
document.write( "hypotenuse of angle 'a' to be 13 (positive because the hypotenuse\r\n" );
document.write( "is the TERMINAL SIDE of the angles which is ALWAYS taken positive.  \r\n" );
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document.write( "Now use an identity for \r\n" );
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document.write( "\"cos%28a-B%29+=+cos%28a%29cos%28B%29%2Bsin%28a%29sin%28B%29\"\r\n" );
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document.write( "\"cos%28a%29=ADJACENT%2FHYPOTENUSE=%28-4%29%2F5=-4%2F5\"\r\n" );
document.write( "\"cos%28B%29=ADJACENT%2FHYPOTENUSE=12%2F13\"\r\n" );
document.write( "\"sin%28a%29=-3%2F5\"   <--given\r\n" );
document.write( "\"sin%28B%29=OPPOSITE%2FHYPOTENUSE=%28-5%29%2F13=-5%2F13\"\r\n" );
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document.write( "Substitute those values in\r\n" );
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document.write( "\"cos%28a-B%29+=+cos%28a%29cos%28B%29%2Bsin%28a%29sin%28B%29\"\r\n" );
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document.write( "and simplify.  You finish.\r\n" );
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document.write( "Edwin
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