document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96451>Question 96451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word Problem for equadratic equations and inequalities.\r<BR>\n" );
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document.write( "An architect has designed a motel pool within a rectangular area that is fenced on three sides.  If she uses 60 yards of fencing to enclose an area of 352 square yards, then what are the dimensions for L and W.  Assume L is greater than W </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70231 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70231\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L+2W=60<BR>\n" );
document.write( "L=60-2W NOW REPLACE L BY(60-2W) IN THE FIRST EQUATION & SOLVE FOR W<BR>\n" );
document.write( "352=(60-2W)W<BR>\n" );
document.write( "352=60W-2W^2<BR>\n" );
document.write( "2W^2-60W+352=0<BR>\n" );
document.write( "2(W^2-30W+176)=0<BR>\n" );
document.write( "2(W-22)(W-8)=0<BR>\n" );
document.write( "W-8=0<BR>\n" );
document.write( "W=8 ANSWER. <BR>\n" );
document.write( "THEN L=60-2*8<BR>\n" );
document.write( "L=60-16<BR>\n" );
document.write( "L=44 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "8*44=352<BR>\n" );
document.write( "352=352<BR>\n" );
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