document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1087987>Question 1087987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessie and Mark are planning to paint a house together. Jessie thinks that if he works alone, it would take him 5 hours more than the time Mark takes to paint the entire house. Working together, they can complete the job in 6 hours.\r<BR>\n" );
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document.write( "QUESTION: If they work together, what equation would repesent the amount of work they can finish in 1 hour?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #702283 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=702283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of time it takes Mark to finish the house. Then Jessie would be n+5. So:<BR>\n" );
document.write( "1/n + 1/n+5=1/6<BR>\n" );
document.write( "6n+30+6n=nē+5n<BR>\n" );
document.write( "nē-7n-30=0<BR>\n" );
document.write( "(n-10)(n+3)=0<BR>\n" );
document.write( "n=10 or -3<BR>\n" );
document.write( "It would take Mark 10 hours to finish the house alone, and Jessie would take 15<BR>\n" );
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