document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96458>Question 96458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in how many ways can 5 boys and 3 girls be arranged so that no two girls may sit together?<BR>\n" );
document.write( "please help me out?i need this answer today.please please................. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70226 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> GBGBGBBB<BR>\n" );
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document.write( "These are all the 20 different versions of 5 Boys and 3 girls.\r<BR>\n" );
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document.write( "However, you can go one step further depending upon what your question implies...\r<BR>\n" );
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document.write( "in each version, the 5 boys can be arranged as b1...b2...b3...b4...b5 or other ways. These are a total of 5! = 5x4x3x2x1 = 120 ways\r<BR>\n" );
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document.write( "Also, the 3 girls can be sat 3! = 6 ways.\r<BR>\n" );
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document.write( "In addition, each version of the boys seating plan allows for all 6 of the girls seating plans so in total there, there are 120x6 = 720 versions.\r<BR>\n" );
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document.write( "so in total there are 20x720 = 14400 different permutations.\r<BR>\n" );
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document.write( "jon. </SPAN>\n" );
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