document.write( "Question 1087968: Perform the indicated integral.
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Algebra.Com's Answer #702242 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "i. ∫ x²exdx\r\n" );
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document.write( " u = x²    dv = exdx\r\n" );
document.write( "du = 2xdx   v = ex\r\n" );
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document.write( "uv - ∫vdu\r\n" );
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document.write( "(x²)ex - ∫ex(2xdx)\r\n" );
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document.write( "(1)     x²ex - 2∫xexdx\r\n" );
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document.write( "Now we do ∫xexdx \r\n" );
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document.write( " u = x     dv = exdx\r\n" );
document.write( "du = dx    v = ex\r\n" );
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document.write( "uv - ∫vdu   \r\n" );
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document.write( "xex - ∫exdx\r\n" );
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document.write( "xex - ex\r\n" );
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document.write( "Now substitute that for the integral in expression (1),\r\n" );
document.write( "and put on the arbitrary constant + C\r\n" );
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document.write( "(1)     x²ex - 2∫xexdx\r\n" );
document.write( "        x²ex - 2(xex - ex)\r\n" );
document.write( "        x²ex - 2xex + 2ex + C\r\n" );
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document.write( "ii. ∫ x ln(x)dx\r\n" );
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document.write( " u = ln(x)     dv = xdx\r\n" );
document.write( "du = \"1%2Fx\"dx       v = \"1%2F2\"x²\r\n" );
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document.write( "You finish.\r\n" );
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document.write( "Edwin
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