document.write( "Question 1087919: Find the standard form of the equation of the parabola with vertex at (5,2) and focus at (3,2). \n" ); document.write( "
Algebra.Com's Answer #702231 by MathTherapy(10557)\"\" \"About 
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Find the standard form of the equation of the parabola with vertex at (5,2) and focus at (3,2).
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Since the focus: (3, 2) is to the LEFT of the VERTEX (5, 2), this is a PARABOLA with a HORIZONTAL AXIS of SYMMETRY. 
\n" ); document.write( "Therefore, the CONIC form of the PARABOLA with a HORIZONTAL AXIS, or \"%28y+-+k%29%5E2+=+4p%28x+-+h%29\" is used.
\n" ); document.write( "h = 5; k = 2 p = – 2
\n" ); document.write( "\"%28y+-+k%29%5E2+=+4p%28x+-+h%29\" becomes:
\n" ); document.write( "\"%28y+-+2%29%5E2+=+4%28-+2%29%28x+-+5%29\"
\n" ); document.write( "\"y%5E2+-+4y+%2B+4+=+-+8x+%2B+40\"
\n" ); document.write( "\"8x+=+-+y%5E2+%2B+4y+%2B+36\"
\n" ); document.write( "\"x+=+%28-+1%2F8%29y%5E2+%2B+%284%2F8%29y+%2B+36%2F8\"
\n" ); document.write( " <======== Equation of parabola \n" ); document.write( "
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