document.write( "Question 96456This question is from textbook Algebra Beginning and Intermediate
\n" ); document.write( ": How many lbs of a 20% copper alloy must be mixed with 600lbs of a 30% copper alloy to make a 27.5% copper alloy?
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Algebra.Com's Answer #70221 by rossiv53(27)\"\" \"About 
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Let x = the amount of 20% copper alloy
\n" ); document.write( "20%x+30%(600)=27.5%(x+600)
\n" ); document.write( "\".20x%2B.30%28600%29=.275%28x%2B600%29\"
\n" ); document.write( "\".20x%2B180=.275x%2B165\"
\n" ); document.write( "\".20x-.275x%2B180=.275x%2B165-.275x\"
\n" ); document.write( "\"-.075x%2B180=165\"
\n" ); document.write( "\"-.075%2B180-180=165-180\"
\n" ); document.write( "\"-.075=-15\"
\n" ); document.write( "\"x=200\"\r
\n" ); document.write( "\n" ); document.write( "x=200 lbs\r
\n" ); document.write( "\n" ); document.write( "Good Luck!
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