document.write( "Question 1087907: Find the probability of this trial, x = 8, n = 11, p = 0.9, where x is successes in n trials.
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\n" ); document.write( "b. 7%
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Algebra.Com's Answer #702190 by jim_thompson5910(35256)\"\" \"About 
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We have n = 11 as the sample size, p = 0.9 as the probability of success, and k = 8 as the number of successes (I'm using k instead of x)\r
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\n" ); document.write( "\n" ); document.write( "Plug in n = 11 and k = 8 into the combination formula below\r
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\n" ); document.write( "\n" ); document.write( "n C k = (n!)/(k!*(n-k)!)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = (11!)/(8!*(11-8)!)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = (11!)/(8!*3!)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = (11*10*9*8!)/(8!*3!)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = (11*10*9)/(3!)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = (11*10*9)/(3*2*1)\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = 990/6\r
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\n" ); document.write( "\n" ); document.write( "11 C 8 = 165\r
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\n" ); document.write( "\n" ); document.write( "Using that combination value, we can say\r
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\n" ); document.write( "\n" ); document.write( "P(X = k) = (n C k)*(p)^(k)*(1-p)^(n-k)\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = (11 C 8)*(0.9)^(8)*(1-0.9)^(11-8)\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = (11 C 8)*(0.9)^(8)*(0.1)^(3)\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = (165)*(0.9)^(8)*(0.1)^3\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = (165)*(0.43046721)*(0.001)\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = 0.07102708965\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = 0.07\r
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\n" ); document.write( "\n" ); document.write( "P(X = 8) = 7% (move the decimal 2 spots to the right to go from 0.07 to 7%)\r
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\n" ); document.write( "\n" ); document.write( "This means that the answer is Choice B
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