document.write( "Question 95820: patty doesn'y feel she is really a child anymore. Ten years ago, her mother was 5 times her age. now she is 3/7 of her mother's age, and in 5 years she will be half of her mother's age. how old will she be when she is half her mother's age? \n" ); document.write( "
Algebra.Com's Answer #70218 by edjones(8007)![]() ![]() You can put this solution on YOUR website! m=mother's age p=patty's age \n" ); document.write( "Now: m=7/3p \n" ); document.write( "10 years ago: m-10=5(p-10) \n" ); document.write( "m-10=5p-50 \n" ); document.write( "substitute 7/3p for m in the line above. 7/3p-10=5p-50 \n" ); document.write( "subtract 7/3p and add 50 to both sides. 40=5p-7/3p \n" ); document.write( "8/3p=40 \n" ); document.write( "divide 8/3 into both sides. p=15 years old m=7/3*15=35 years old \n" ); document.write( "When will she be 1/2 her mother's age? \n" ); document.write( "2(15+x)=35+x \n" ); document.write( "30+2x=35+x \n" ); document.write( "subtract x and 30 from both sides. x=5 years \n" ); document.write( "Check: \n" ); document.write( "now: 35*3/7=15 she is 3/7 mom's age \n" ); document.write( "10 years ago: p=5 m=25 mother was 5x her age. \n" ); document.write( "in 5 years: p=20 m=40 she will be 1/2 mom's age. \n" ); document.write( "EdJones \n" ); document.write( " \n" ); document.write( " |