document.write( "Question 1087856: Hi,\r
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\n" ); document.write( "\n" ); document.write( "GIven that y is always positive and z is always negative, solve 2xyz + yz > 3xyz for x\r
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Algebra.Com's Answer #702128 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
yz < 0
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\n" ); document.write( "-2xyz - yz > -3xyz
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\n" ); document.write( "add 3xyz to both sides of >
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\n" ); document.write( "xyz > yz
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\n" ); document.write( "x > 1
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