document.write( "Question 1087856: Hi,\r
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document.write( "How do I solve this inequality?\r
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document.write( "GIven that y is always positive and z is always negative, solve 2xyz + yz > 3xyz for x\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #702128 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! yz < 0 \n" ); document.write( ": \n" ); document.write( "-2xyz - yz > -3xyz \n" ); document.write( ": \n" ); document.write( "add 3xyz to both sides of > \n" ); document.write( ": \n" ); document.write( "xyz > yz \n" ); document.write( ": \n" ); document.write( "******* \n" ); document.write( "x > 1 \n" ); document.write( "******* \n" ); document.write( ": \n" ); document.write( " |