document.write( "Question 1087745: The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes? \n" ); document.write( "
Algebra.Com's Answer #702064 by mathmate(429)\"\" \"About 
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Question:
\n" ); document.write( "The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes?
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\n" ); document.write( "Solution:
\n" ); document.write( "mean=μ=64 minutes
\n" ); document.write( "sd=σ=18 minutes
\n" ); document.write( "normal distribution N(64,18)
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\n" ); document.write( "Need P(64\n" ); document.write( "
\n" ); document.write( "P(64\n" ); document.write( "=P((64-μ)/σ < z < (100-&mul)/σ)
\n" ); document.write( "=P((64-64)/18 < z < (100-64)/18)
\n" ); document.write( "=P(0 < z < 2)
\n" ); document.write( "=P(z<2)-P(z<0)
\n" ); document.write( "=0.9772499-0.5 [ from tables ]
\n" ); document.write( "=0.47725
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