document.write( "Question 1087753: 1. Twenty-three percent of Ole Miss students are from out of state. In a random sample of 6 students, what is the probability that at least 2 of them are from out of state?(round to whole number)
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document.write( "a. 42% b. 7% c. 28% d. 64% e. none of these\r
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document.write( "2. For the problem above what is the expected value of x.
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document.write( "a. 4.2 b. 2.7 c. 1.4 d. .5 e. none of these
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Algebra.Com's Answer #702063 by mathmate(429)![]() ![]() You can put this solution on YOUR website! Question: \n" ); document.write( "1. Twenty-three percent of Ole Miss students are from out of state. In a random sample of 6 students, what is the probability that at least 2 of them are from out of state?(round to whole number) \n" ); document.write( "a. 42% b. 7% c. 28% d. 64% e. none of these \n" ); document.write( "2. For the problem above what is the expected value of x. \n" ); document.write( "a. 4.2 b. 2.7 c. 1.4 d. .5 e. none of these \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "Since the probability is known and constant (large population), the binomial distribution can be used to model the situation. \n" ); document.write( "p=0.23 \n" ); document.write( "n=6 \n" ); document.write( "(1) At least two student from out-of-state. \n" ); document.write( "P(x)=C(n,x)p^(x)*(1-p)^(n-x) \n" ); document.write( "=1-C(6,0)(0.23)^0*(0.77)^6-C(6,1)(0.23)^1*(0.77)^5 \n" ); document.write( "=1-0.2084-0.3735 \n" ); document.write( "=0.4180\r \n" ); document.write( "\n" ); document.write( "(2) Expected value of x \n" ); document.write( "Expected value of x (in a binomial distribution) \n" ); document.write( "=np \n" ); document.write( "=6*0.23 \n" ); document.write( "=1.38 \n" ); document.write( " |