document.write( "Question 1087742: A large watermelon weighs 20kg with 96% of its weight being water. it is allowed to stand in the sun and some of the water evaporates so that only 95% of its weight is water. it's reduced weight will be? \n" ); document.write( "
Algebra.Com's Answer #702034 by KMST(5328)\"\" \"About 
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Some of the water goes away, but the part that is not water stays.
\n" ); document.write( "How much was that part by mass at the start?
\n" ); document.write( "It was \"%22100%25%22-%2296%25%22=%224%25%22=4%2F100=1%2F25=0.04\" of the total.
\n" ); document.write( "In terms of mass, it was \"0.04%2A20kg=0.8kg\" .
\n" ); document.write( "At the end, there were still \"0.8kg\" of stuff that was not water in the shriveled watermelon,
\n" ); document.write( "but then it made up \"%22100%25%22-%2295%25%22=%225%25%22=5%2F100=1%2F20=0.05\" of the total.
\n" ); document.write( "So the total mass of that shriveled, sun-baked watermelon ended up as
\n" ); document.write( "\"m=20%2A0.8kg=highlight%2816kg%29\" or \"m=0.8kg%2F0.05=highlight%2816kg%29\" .
\n" ); document.write( "You could say that the final mass, \"m\" is such that
\n" ); document.write( "\"%225%25%22=5%2F100=0.05\" of it is water;
\n" ); document.write( "write \"0.05m=0.8kg\" as an equation,
\n" ); document.write( "and \"solve for m\" to get
\n" ); document.write( "\"m=0.8kg%2F0.05=highlight%2816kg%29\" ,
\n" ); document.write( "to say you are using algebra.
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