document.write( "Question 1087632: The local park measures 60 m by 50 m. Part of the park is torn up to install a sidewalk of uniform width about it, reducing the area of the park itself by 321 m2. How wide is the sidewalk? \n" ); document.write( "
Algebra.Com's Answer #701979 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let l be the length of the internal rectangle and w be the width of the internal rectangle \n" ); document.write( ": \n" ); document.write( "1) (l+2x) * (w+2x) = 3000 \n" ); document.write( "2) 2(l+2x) + 2(w+2x) = 220 \n" ); document.write( "3) l * w = 3000 - 321 = 2679 \n" ); document.write( ": \n" ); document.write( "expand equation 1 by multiplication of left side of = \n" ); document.write( ": \n" ); document.write( "lw +2xw +2xl +4x^2 = 3000 \n" ); document.write( "4) 4x^2 +2x(w+l) = 321 \n" ); document.write( ": \n" ); document.write( "use equation 2 to get expression for w+l \n" ); document.write( ": \n" ); document.write( "l +w + 4x = 110 \n" ); document.write( "l +w = 110-4x \n" ); document.write( ": \n" ); document.write( "substitute for l+w in equation 4 \n" ); document.write( ": \n" ); document.write( "4x^2 +2x(110-4x) = 321 \n" ); document.write( ": \n" ); document.write( "4x^2 +220x -8x^2 = 321 \n" ); document.write( "4x^2 -220x +321 = 0 \n" ); document.write( ": \n" ); document.write( "use quadratic formula to solve for x \n" ); document.write( ": \n" ); document.write( "x = (-(-220) + square root((-220)^2 -4*4*321)) / 2(4) = 53.5 \n" ); document.write( "x = (-(-220) - square root((-220)^2 -4*4*321)) / 2(4) = 1.5 \n" ); document.write( ": \n" ); document.write( "we accept x = 1.5 m \n" ); document.write( ": \n" ); document.write( "****************************** \n" ); document.write( "the sidewalk is 1.5 m wide \n" ); document.write( "****************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |